Master Cramer's Rule: Solve $5x+8y=14$, $6x+8y=-2$

by Admin 51 views
Master Cramer's Rule: Solve $5x+8y=14$, $6x+8y=-2$

Hey there, math enthusiasts and problem-solvers! Ever found yourself staring down a system of linear equations and wishing you had a secret weapon to conquer it? Well, guys, today we're pulling out one of the coolest tools in the algebraic arsenal: Cramer's Rule. This isn't just some abstract theory; it's a super practical and systematic way to nail down those tricky x and y values without breaking a sweat, especially for smaller systems like the one we're about to tackle. We're talking about finding the solution for the specific system: 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2. If you've ever felt overwhelmed by substitution or elimination, get ready for a fresh, powerful perspective.

A system of linear equations is basically a set of two or more linear equations that share the same variables. The goal is to find the values of these variables that satisfy all equations simultaneously. Think of it like a puzzle where all pieces have to fit perfectly. For our example, we have two equations, 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2, and we're looking for a single pair of (x,y)(x, y) values that makes both statements true. While methods like substitution or elimination work perfectly fine, Cramer's Rule offers a unique advantage: it's incredibly structured and relies on a concept called determinants, which might sound fancy but is actually quite straightforward once you get the hang of it. It’s particularly useful when you want a clear, formulaic approach, or when dealing with larger systems where elimination can become cumbersome. So, buckle up! We're about to dive deep into how Cramer's Rule makes solving these linear systems not just possible, but genuinely enjoyable.

What Exactly is Cramer's Rule? A Friendly Dive into Determinants

Alright, let's get down to brass tacks: what's the deal with Cramer's Rule and these mysterious things called determinants? Don't worry, it's not as complex as it sounds! At its heart, Cramer's Rule is a method that uses determinants of matrices to solve systems of linear equations. So, before we get to the rule itself, we need to understand what a determinant is. For a simple 2x2 matrix, which is what we'll be dealing with for our two-variable system, calculating the determinant is a piece of cake. Imagine you have a matrix like this:

∣ab cd∣\begin{vmatrix} a & b \ c & d \end{vmatrix}

The determinant of this matrix is calculated by simply multiplying the elements on the main diagonal (top-left to bottom-right) and subtracting the product of the elements on the anti-diagonal (top-right to bottom-left). So, the determinant would be ad - bc. Pretty simple, right? For example, if you had ∣34Β 12∣\begin{vmatrix} 3 & 4 \ 1 & 2 \end{vmatrix}, the determinant would be (3Γ—2)βˆ’(4Γ—1)=6βˆ’4=2(3 \times 2) - (4 \times 1) = 6 - 4 = 2. This fundamental calculation is the bedrock upon which Cramer's Rule is built.

Now, how does Cramer's Rule actually use these determinants to find x and y? It gives us neat formulas: x=Dx/Dx = D_x / D and y=Dy/Dy = D_y / D. Here, D represents the determinant of the main coefficient matrix (the numbers in front of x and y from our original equations). D_x is the determinant of a modified matrix where the x-coefficients are replaced by the constants from the right side of the equations. Similarly, D_y is the determinant of another modified matrix where the y-coefficients are replaced by those same constants. The beauty of Cramer's Rule lies in its consistency and directness. You calculate these three determinants and then, boom, you've got your x and y! It's super important to remember that D cannot be zero for Cramer's Rule to work; if it is, the system either has no unique solution or no solution at all, which is an important point we'll revisit later. Understanding these determinants is your first major step in mastering this powerful rule, setting you up for success in solving any linear system thrown your way.

Setting Up Our System: 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2 in Matrix Form

Alright, team, let's take our specific challenge, the system of linear equations: 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2, and get it ready for the magic of Cramer's Rule. The first crucial step is to represent this system in its matrix form. This might sound a bit intimidating if you're new to matrices, but trust me, it’s just an organized way of writing down the numbers. When we put our linear equations into matrix form, we essentially separate the coefficients, the variables, and the constants into distinct matrices.

For a general system like: ax+by=eax + by = e cx+dy=fcx + dy = f

It can be written as:

(abΒ cd)(xΒ y)=(eΒ f)\begin{pmatrix} a & b \ c & d \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} e \ f \end{pmatrix}

See? We have the coefficient matrix on the left, which contains all the numbers multiplying our variables, followed by the variable matrix (which just holds x and y), and finally, the constant matrix on the right side of the equals sign. This setup is absolutely essential for applying Cramer's Rule correctly, as each of our determinants (DD, DxD_x, DyD_y) will be derived directly from these matrices. For our specific problem, 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2, let’s identify these components:

  • The coefficients of x are 5 and 6.
  • The coefficients of y are 8 and 8.
  • The constants on the right side are 14 and -2.

So, our coefficient matrix will be:

(58Β 68)\begin{pmatrix} 5 & 8 \ 6 & 8 \end{pmatrix}

The variable matrix is always:

(xΒ y)\begin{pmatrix} x \ y \end{pmatrix}

And the constant matrix is:

(14Β βˆ’2)\begin{pmatrix} 14 \ -2 \end{pmatrix}

Putting it all together, our system in matrix form looks like this:

(58Β 68)(xΒ y)=(14Β βˆ’2)\begin{pmatrix} 5 & 8 \ 6 & 8 \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} 14 \ -2 \end{pmatrix}

This careful transcription is a really important step. Any small error here can throw off all your subsequent calculations. By clearly defining these matrices, we've laid the groundwork for the next, most exciting part: calculating the determinants that will directly lead us to our solution for x and y using Cramer's Rule. So, take a moment, ensure everything is correctly identified, and let's move on to the actual number crunching!

Step-by-Step Calculation: Finding D, D_x, and D_y

Now for the real fun part, guys! We're going to roll up our sleeves and perform the core calculations required by Cramer's Rule. This involves finding three key determinants: DD, DxD_x, and DyD_y. Each one plays a vital role in unlocking the solution to our system of linear equations. Remember, precision is our best friend here, so let's walk through each determinant calculation step by step.

Calculating the Main Determinant (D)

The main determinant, D, is calculated from our coefficient matrix. This matrix is made up of the numbers in front of x and y from our original equations: 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2. So, our coefficient matrix is:

∣58 68∣\begin{vmatrix} 5 & 8 \ 6 & 8 \end{vmatrix}

To find D, we apply the 2x2 determinant formula: (aΓ—d)βˆ’(bΓ—c)(a \times d) - (b \times c).

Here, a=5a=5, b=8b=8, c=6c=6, and d=8d=8.

Let's calculate: D=(5Γ—8)βˆ’(8Γ—6)D = (5 \times 8) - (8 \times 6) D=40βˆ’48D = 40 - 48 D=βˆ’8D = -8

So, our main determinant, D, is -8. This value is crucial because it will be the denominator for both x and y in Cramer's Rule. A non-zero D means we're on the right track for a unique solution!

Calculating the Determinant for x (D_x)

Next up, we need to find D_x. For this determinant, we take our original coefficient matrix and replace the x-coefficients (the first column) with the constant terms from the right side of our equations (14 and -2). The y-coefficients (the second column) stay exactly the same.

The matrix for D_x will look like this:

∣148Β βˆ’28∣\begin{vmatrix} 14 & 8 \ -2 & 8 \end{vmatrix}

Again, using the formula (aΓ—d)βˆ’(bΓ—c)(a \times d) - (b \times c):

Here, a=14a=14, b=8b=8, c=βˆ’2c=-2, and d=8d=8.

Let's calculate: Dx=(14Γ—8)βˆ’(8Γ—βˆ’2)D_x = (14 \times 8) - (8 \times -2) Dx=112βˆ’(βˆ’16)D_x = 112 - (-16) Dx=112+16D_x = 112 + 16 Dx=128D_x = 128

So, D_x is 128. See how Cramer's Rule systematically modifies the matrices? It’s pretty neat!

Calculating the Determinant for y (D_y)

Finally, we calculate D_y. This time, we go back to our original coefficient matrix and replace the y-coefficients (the second column) with the constant terms (14 and -2). The x-coefficients (the first column) remain unchanged.

The matrix for D_y will look like this:

∣514Β 6βˆ’2∣\begin{vmatrix} 5 & 14 \ 6 & -2 \end{vmatrix}

Applying the determinant formula (aΓ—d)βˆ’(bΓ—c)(a \times d) - (b \times c) one last time:

Here, a=5a=5, b=14b=14, c=6c=6, and d=βˆ’2d=-2.

Let's calculate: Dy=(5Γ—βˆ’2)βˆ’(14Γ—6)D_y = (5 \times -2) - (14 \times 6) Dy=βˆ’10βˆ’84D_y = -10 - 84 Dy=βˆ’94D_y = -94

And there you have it, D_y is -94. We've successfully calculated all three necessary determinants using the systematic process laid out by Cramer's Rule. These values, D=βˆ’8D = -8, Dx=128D_x = 128, and Dy=βˆ’94D_y = -94, are our tickets to finding the solution. The clarity and directness of these steps highlight why Cramer's Rule is such a valued method in solving systems of linear equations for many students and professionals alike. Next, we'll combine these results to get our final x and y values!

Unveiling the Solution: Finding x and y

Alright, folks, we've done the heavy lifting! We’ve meticulously calculated our three determinants: D=βˆ’8D = -8, Dx=128D_x = 128, and Dy=βˆ’94D_y = -94. Now comes the moment of truth, where we use these values to unveil the solution to our system of linear equations using the elegant formulas from Cramer's Rule. This is where all our hard work pays off!

Remember the formulas for x and y that Cramer's Rule provides?

x=Dx/Dx = D_x / D y=Dy/Dy = D_y / D

Let's plug in our numbers and get those variable values:

For x: x=128/βˆ’8x = 128 / -8 x=βˆ’16x = -16

And for y: y=βˆ’94/βˆ’8y = -94 / -8 y=47/4y = 47 / 4 y=11.75y = 11.75

So, the solution to our system of equations, 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2, is x=βˆ’16x = -16 and y=47/4y = 47/4 (or 11.75). This is the unique pair of values that satisfies both equations simultaneously. How cool is that? Cramer's Rule delivered a clear and direct path to our answer.

But wait, a good mathematician (and problem-solver!) always checks their work. Let's substitute these values back into our original equations to make sure they hold true. This verification step is super important to ensure we didn't make any calculation errors along the way. It's like double-checking your recipe before serving dinner!

Equation 1: 5x+8y=145x+8y=14 5(βˆ’16)+8(47/4)=145(-16) + 8(47/4) = 14 βˆ’80+(8/4Γ—47)=14-80 + (8/4 \times 47) = 14 βˆ’80+(2Γ—47)=14-80 + (2 \times 47) = 14 βˆ’80+94=14-80 + 94 = 14 14=1414 = 14 (Checks out!)

Equation 2: 6x+8y=βˆ’26x+8y=-2 6(βˆ’16)+8(47/4)=βˆ’26(-16) + 8(47/4) = -2 βˆ’96+(2Γ—47)=βˆ’2-96 + (2 \times 47) = -2 βˆ’96+94=βˆ’2-96 + 94 = -2 βˆ’2=βˆ’2-2 = -2 (Checks out again!)

Both equations are satisfied! This confirms that our solution for x and y is correct. We successfully applied Cramer's Rule to solve this linear system, from setting up the matrices to calculating the determinants and finally, deriving and verifying the solution. Pat yourselves on the back, you guys just mastered a powerful mathematical technique!

Why Cramer's Rule Rocks (and When it Doesn't)

So, we've successfully used Cramer's Rule to solve a system of linear equations, and hopefully, you're feeling pretty empowered. But let's take a moment to discuss why Cramer's Rule rocks, and equally important, when it doesn't. Understanding its advantages and limitations will help you pick the best tool for future mathematical challenges.

One of the biggest advantages of Cramer's Rule is its systematic approach. Each step is clearly defined: identify coefficients, form determinants, calculate determinants, and finally, divide. This makes it a fantastic method for students learning to solve linear equations, as it reduces the potential for getting lost in algebraic manipulation. For smaller systems, especially 2x2 and 3x3, it's often faster and more direct than methods like substitution or elimination, particularly if the coefficients are messy fractions or decimals. It gives you a direct formula for each variable, which can be super convenient. Plus, it gives you a clear indicator (when D=0) if a unique solution doesn't exist, which is valuable information in itself. This directness means you don't have to worry about back-substitution or complex algebraic steps that can sometimes lead to errors. It’s a clean, formulaic path to the answer.

However, like any tool, Cramer's Rule has its limitations. The main one is its computational intensity for larger systems. While it's great for 2x2 or 3x3 systems, imagine trying to calculate four 4x4 determinants (D, Dx, Dy, Dz) for a system with four variables! The number of calculations explodes, making it far less efficient than other methods like Gaussian elimination or matrix inversion, especially when performed by hand. Modern computational tools can handle larger determinants easily, but for manual work, it quickly becomes cumbersome. Another significant limitation, which we briefly touched upon, is when the main determinant D equals zero. If D=0, Cramer's Rule cannot be used because you cannot divide by zero. This scenario indicates that the system of linear equations either has no solution (parallel lines in 2D, parallel planes in 3D) or infinitely many solutions (overlapping lines or planes). In these cases, you'd need to revert to methods like Gaussian elimination to determine the exact nature of the solution set.

So, when would you choose Cramer's Rule? Definitely for quick, precise solutions to 2x2 and 3x3 systems. It's fantastic for homework problems, standardized tests, or anytime you appreciate a clear, step-by-step formula. When dealing with bigger systems, or when computational efficiency is paramount, other methods might be your go-to. Regardless, understanding Cramer's Rule enriches your mathematical toolkit by providing a powerful and elegant way to conceptualize and solve linear equations through the lens of determinants.

Conclusion

And there you have it, folks! We've journeyed through the fascinating world of Cramer's Rule, from understanding its fundamental components to applying it to a real-world system of linear equations. We successfully tackled 5x+8y=145x+8y=14 and 6x+8y=βˆ’26x+8y=-2, uncovering the unique solution of x=βˆ’16x=-16 and y=47/4y=47/4. We broke down each step, calculating the main determinant D=βˆ’8D=-8, Dx=128D_x=128, and Dy=βˆ’94D_y=-94, and then efficiently used these values to find our variables.

This method, rooted in the elegant concept of determinants, provides a systematic and often aesthetically pleasing way to solve linear systems. It's a testament to how mathematical tools can simplify complex problems into manageable steps. Remember, practice makes perfect! The more you apply Cramer's Rule to different systems of equations, the more comfortable and confident you'll become. Keep exploring, keep questioning, and keep solving. Math is an adventure, and you've just mastered another incredible skill on your journey!